A nucleus _Z^AX emits an alpha-particle. The | vedclass

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(A) $1$. The initial nucleus is $_Z^AX$. $2$. When it emits an $\alpha$-particle $( _2^4He )$,the atomic number decreases by $2$ and the mass number d

Vedclass · Accepted Answer

$Z - 3, A - 4$

Vedclass · Answer

(A) $1$. The initial nucleus is $_Z^AX$. $2$. When it emits an $\alpha$-particle $( _2^4He )$,the atomic number decreases by $2$ and the mass number decreases by $4$. The reaction is: $_Z^AX 	o _{Z - 2}^{A - 4}Y + _2^4He$. $3$. The resultant nucleus $_{Z - 2}^{A - 4}Y$ then emits a ${\beta ^ + }$ particle (positron,$ _{+1}^0e $). During ${\beta ^ + }$ decay,the atomic number decreases by $1$ while the mass number remains unchanged. $4$. The reaction is: $_{Z - 2}^{A - 4}Y 	o _{Z - 3}^{A - 4}Z' + _{+1}^0e$. $5$. Thus,the final nucleus has an atomic number of $Z - 3$ and a mass number of $A - 4$.

List-$I$	List-$II$
$(P)$ ${ }_{92}^{238} U \rightarrow{ }_{91}^{234} Pa$	$(1)$ $1 \alpha$ and $1 \beta^{+}$
$(Q)$ ${ }_{82}^{214} Pb \rightarrow{ }_{82}^{210} Pb$	$(2)$ $3 \beta^{-}$ and $1 \alpha$
$(R)$ ${ }_{81}^{210} Tl \rightarrow{ }_{82}^{206} Pb$	$(3)$ $2 \beta^{-}$ and $1 \alpha$
$(S)$ ${ }_{91}^{228} Pa \rightarrow{ }_{88}^{224} Ra$	$(4)$ $1 \alpha$ and $1 \beta^{-}$
	$(5)$ $1 \alpha$ and $2 \beta^{+}$

$A$ nucleus $_Z^AX$ emits an $\alpha$-particle. The resultant nucleus then emits a ${\beta ^ + }$ particle. What will be the respective atomic number and mass number of the final nucleus?

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