A number is increased by 84,it becomes 107 % | vedclass

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Question

(A) Let the number be $x$.According to the problem,when the number is increased by $84$,it becomes $107 \%$ of itself.So,$x + 84 = 1.07x$.Rearranging

Vedclass · Accepted Answer

$1200$

Vedclass · Answer

(A) Let the number be $x$.According to the problem,when the number is increased by $84$,it becomes $107 \%$ of itself.So,$x + 84 = 1.07x$.Rearranging the equation: $84 = 1.07x - x$.$84 = 0.07x$.$x = \frac{84}{0.07} = \frac{8400}{7} = 1200$.Alternatively,the increase of $84$ represents $107 \% - 100 \% = 7 \%$ of the number.$7 \%$ of the number $= 84$.$	herefore 100 \%$ of the number $= \frac{84}{7} 	imes 100 = 1200$.

$A$ number is increased by $84$,it becomes $107 \%$ of itself. What is the number?

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