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(C) Let the sample space for two children be $S = \{BB, BG, GB, GG\}$,where $B$ denotes a boy and $G$ denotes a girl. The total number of outcomes is

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$1/3$

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(C) Let the sample space for two children be $S = \{BB, BG, GB, GG\}$,where $B$ denotes a boy and $G$ denotes a girl. The total number of outcomes is $4$.Let $A$ be the event that at least one child is a boy. Then $A = \{BB, BG, GB\}$. The number of outcomes in $A$ is $3$.Let $B$ be the event that both children are boys. Then $B = \{BB\}$.We need to find the conditional probability $P(B|A)$,which is the probability that both are boys given that at least one is a boy.Using the formula for conditional probability: $P(B|A) = \frac{P(A \cap B)}{P(A)}$.Here,$A \cap B = \{BB\}$,so $P(A \cap B) = 1/4$.$P(A) = 3/4$.Therefore,$P(B|A) = \frac{1/4}{3/4} = 1/3$.

$A$ couple has two children. If at least one of them is a boy,what is the probability that the other is also a boy?

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