(A) The displacement current $I_d$ in a capacitor is defined as the rate of change of charge on the plates,which is equal to the conduction current $I

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(A) The displacement current $I_d$ in a capacitor is defined as the rate of change of charge on the plates,which is equal to the conduction current $I_c$ flowing into the capacitor.Mathematically,$I_d = I_c = \frac{dq}{dt}$.Given that the rate of loss of charge is $\frac{dq}{dt} = 1.8 \times 10^{-8}\, C/s$.Therefore,the magnitude of the displacement current is $I_d = 1.8 \times 10^{-8}\, A$.

Class 12 Physics Electromagnetic Waves Maxwell's equations , Concept of displacement current and Hertz experiment

Easy

$A$ parallel plate capacitor is charged to $60\,\mu C$. Due to a radioactive source,the plate loses charge at the rate of $1.8 \times 10^{-8}\, C/s$. The magnitude of the displacement current is:

A
$1.8 \times 10^{-8}\, A$
B
$3.6 \times 10^{-8}\, A$
C
$1.1 \times 10^{-11}\, A$
D
$5.7 \times 10^{-12}\, A$

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Electromagnetic Waves

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Maxwell's equations , Concept of displacement current and Hertz experiment

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$A$ parallel plate capacitor is charged to $60\,\mu C$. Due to a radioactive source,the plate loses charge at the rate of $1.8 \times 10^{-8}\, C/s$. The magnitude of the displacement current is:

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Describe the research conducted by scientists regarding electricity and magnetism following Oersted's observation.

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$A$ quantity $X$ is given by $\varepsilon_0 L \frac{\Delta V}{\Delta t}$, where $\varepsilon_0$ is the permittivity of free space, $L$ is the length, $\Delta V$ is a potential difference, and $\Delta t$ is a time interval. The dimension of $X$ is the same as that of

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