A parallel plate capacitor with plate area A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The charge on the capacitor plates at time $t$ is $q = It$.The electric field $E$ between the plates at this instant is given by $E = \frac{q}{A \

Vedclass · Accepted Answer

$I/2$

Vedclass · Answer

(B) The charge on the capacitor plates at time $t$ is $q = It$.The electric field $E$ between the plates at this instant is given by $E = \frac{q}{A \varepsilon_0} = \frac{It}{A \varepsilon_0}$.The electric flux $\phi_E$ through the given area $A/2$ is $\phi_E = E \cdot \left(\frac{A}{2}\right) = \left(\frac{It}{A \varepsilon_0}\right) \cdot \left(\frac{A}{2}\right) = \frac{It}{2 \varepsilon_0}$.The displacement current $I_D$ is defined as $I_D = \varepsilon_0 \frac{d\phi_E}{dt}$.Substituting the expression for $\phi_E$,we get $I_D = \varepsilon_0 \frac{d}{dt} \left(\frac{It}{2 \varepsilon_0}\right) = \varepsilon_0 \cdot \frac{I}{2 \varepsilon_0} = \frac{I}{2}$.

$A$ parallel plate capacitor with plate area $A$ and separation between the plates $d$ is charged by a constant current $I$. Consider a plane surface of area $A/2$ parallel to the plates and drawn between the plates. The displacement current through the area is

Similar Questions

If $\cos 2x = (\sqrt{2} + 1) \left(\cos x - \frac{1}{\sqrt{2}}\right)$ and $\cos x \neq \frac{1}{\sqrt{2}}$,then $x \in$

If a straight line $L$ is perpendicular to the line $4x - 2y = 1$ and forms a triangle of area $4 \text{ sq unit}$ with the coordinate axes,then the equation of the line $L$ is

The biquadratic equation,two of whose roots are $1+i$ and $1-\sqrt{2}$,is

If $|a| = 2$,$|b| = 3$ and $a, b$ are mutually perpendicular,then the area of the triangle whose vertices are $0, a + b, a - b$ is

Which of the following statements is false?

Vedclass Test Series

Exam Paper Generator

Online Exam Module