$A$ parallel plate capacitor is filled with two dielectrics as shown in the figure. The area of each plate is $A \; m^2$ and the separation between the plates is $t \; m$. The dielectric constants are $k_1$ and $k_2$ respectively. Its capacitance in farad will be:

  • A
    $\frac{\varepsilon_0 A}{t}(k_1 + k_2)$
  • B
    $\frac{\varepsilon_0 A}{t} \cdot \frac{k_1 + k_2}{2}$
  • C
    $\frac{2\varepsilon_0 A}{t}(k_1 + k_2)$
  • D
    $\frac{\varepsilon_0 A}{t} \cdot \frac{k_1 - k_2}{2}$

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