(A) For both particles,the vertical motion is governed by the equation of motion $h = ut + \frac{1}{2}gt^2$. Since both particles are released from th

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Both particles will reach the ground simultaneously.

(A) For both particles,the vertical motion is governed by the equation of motion $h = ut + \frac{1}{2}gt^2$. Since both particles are released from the same height $h$ and their initial vertical velocity component $u_y$ is $0$ in both cases,the time taken to reach the ground is given by $t = \sqrt{\frac{2h}{g}}$. Since $h$ and $g$ are the same for both,the time taken $t$ is identical for both particles. Therefore,both particles will reach the ground simultaneously.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Easy

$A$ particle $(A)$ is dropped from a height and another particle $(B)$ is thrown in a horizontal direction with a speed of $5 \; m/s$ from the same height. The correct statement is:

AIPMT 2002 All AIPMT

A
Both particles will reach the ground simultaneously.
B
Both particles will reach the ground with the same speed.
C
Particle $(A)$ will reach the ground first with respect to particle $(B)$.
D
Particle $(B)$ will reach the ground first with respect to particle $(A)$.

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3-2.Motion in Plane

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Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $(90^{\circ}-\alpha)$ with the same speed from the same point. The ratio of their maximum heights is

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For a projectile, if $\alpha$ is the angle of projection, $R$ is the range, $h$ is the maximum height, and $T$ is the time of flight, then:

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$A$ projectile is thrown with an initial velocity of $10 \ m/s$ at an angle $\alpha$ with the horizontal. It has a range of $5 \ m$. Taking $g = 10 \ m/s^2$ and neglecting air resistance, what will be the estimated value of $\alpha$ (in $^{\circ}$)?

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$A$ particle $(A)$ is dropped from a height and another particle $(B)$ is thrown in a horizontal direction with a speed of $5 \; m/s$ from the same height. The correct statement is:

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The horizontal and vertical displacements $x$ and $y$ of a projectile at a given time $t$ are given by $x = 6t \text{ m}$ and $y = 8t - 5t^2 \text{ m}$. The range of the projectile in metres is:

Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $(90^{\circ}-\alpha)$ with the same speed from the same point. The ratio of their maximum heights is

For a projectile, if $\alpha$ is the angle of projection, $R$ is the range, $h$ is the maximum height, and $T$ is the time of flight, then:

$A$ projectile is thrown with an initial velocity of $10 \ m/s$ at an angle $\alpha$ with the horizontal. It has a range of $5 \ m$. Taking $g = 10 \ m/s^2$ and neglecting air resistance, what will be the estimated value of $\alpha$ (in $^{\circ}$)?

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