(C) The acceleration $a$ of a particle in simple harmonic motion is given by $a = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the d

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(C) The acceleration $a$ of a particle in simple harmonic motion is given by $a = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the displacement.Given $a = 0.5 \, m/s^2$ and $y = 0.02 \, m$.$\omega^2 = \frac{a}{y} = \frac{0.5}{0.02} = 25$.$\omega = \sqrt{25} = 5 \, rad/s$.The maximum velocity $v_{\max}$ is given by $v_{\max} = A\omega$,where $A$ is the amplitude.Given $A = 0.1 \, m$.$v_{\max} = 0.1 \times 5 = 0.5 \, m/s$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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$A$ particle is executing simple harmonic motion with an amplitude of $0.1 \, m$. At a certain instant when its displacement is $0.02 \, m$,its acceleration is $0.5 \, m/s^2$. The maximum velocity of the particle is (in $m/s$):

A
$0.01$
B
$0.05$
C
$0.5$
D
$0.25$

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Acceleration and Force of Simple Harmonic Motion

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$A$ particle is executing simple harmonic motion with an amplitude of $0.1 \, m$. At a certain instant when its displacement is $0.02 \, m$,its acceleration is $0.5 \, m/s^2$. The maximum velocity of the particle is (in $m/s$):

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