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(A) The maximum velocity $(V_{\max})$ of a particle in simple harmonic motion is given by the formula: $V_{\max} = \omega A$.Here, $\omega$ is the ang

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The maximum velocity $(V_{\max})$ of a particle in simple harmonic motion is given by the formula: $V_{\max} = \omega A$.Here, $\omega$ is the angular frequency and $A$ is the amplitude.We know that $\omega = \frac{2\pi}{T}$, where $T$ is the time period.Given: $A = 0.06 \,m$ and $T = 3.14 \,s \approx \pi \,s$.Substituting the values:$V_{\max} = \left(\frac{2\pi}{\pi}ight) 	imes 0.06 = 2 	imes 0.06 = 0.12 \,m/s$.To convert the velocity into $cm/s$, we multiply by $100$:$V_{\max} = 0.12 	imes 100 = 12 \,cm/s$.

$A$ particle is performing simple harmonic motion with an amplitude of $0.06 \,m$ and a time period of $3.14 \,s$. The maximum velocity of the particle is . . . . . . $cm/s$.

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