$A$ particle is dropped under gravity from rest from a height $h$ $(g = 9.8 \ m/s^2)$. If it travels a distance of $9h/25$ in the last second of its motion,the height $h$ is ......... $m$.

$A$ ball is projected vertically upwards from the ground. It reaches a height $h$ in time $t_1$,continues its motion,and then takes a time $t_2$ to reach the ground. The height $h$ in terms of $g, t_1$,and $t_2$ is ($g =$ acceleration due to gravity).

$A$ ball is thrown vertically upwards with a velocity of $15 \ m/s$. To what maximum height will it reach? (Take $g = 10 \ m/s^2$)

$A$ ball is dropped downwards. After $1$ second,another ball is dropped downwards from the same point. What is the distance between them after $3$ seconds?

$A$ body falls from a height $h = 200\,m$ (at New Delhi). The ratio of distance travelled in each $2\,s$ interval during $t = 0$ to $t = 6\,s$ of the journey is

$A$ ball is thrown upwards. Its height varies with time as shown in the graph. If the acceleration due to gravity is $g = 7.5\, m/s^2$,then the height $h$ is.........$m$.