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(C) Let the initial position of the particle be $A$ and the final position be $B$ on a circular path of radius $r$. The angle subtended at the center

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$r$

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(C) Let the initial position of the particle be $A$ and the final position be $B$ on a circular path of radius $r$. The angle subtended at the center $O$ is $	heta = 60^{\circ}$.The displacement is the straight-line distance between $A$ and $B$,denoted by $x$.In $	riangle OAB$,$OA = OB = r$ and $\angle AOB = 60^{\circ}$.Since two sides are equal and the included angle is $60^{\circ}$,the triangle is equilateral.Therefore,the third side $x = AB = r$.

$A$ particle is moving on a circular path of radius $r$ with uniform speed $v$. What is the displacement of the particle after it has described an angle of $60^{\circ}$?

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