A particle is moving on a circular path with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The velocity of a particle moving in a circular path with constant speed $v$ is a vector quantity. Let the velocity at point $A$ be $\vec{v}_A$ an

Vedclass · Accepted Answer

$v, 0$

Vedclass · Answer

(B) The velocity of a particle moving in a circular path with constant speed $v$ is a vector quantity. Let the velocity at point $A$ be $\vec{v}_A$ and at point $B$ be $\vec{v}_B$. The magnitude of both is $v$.The magnitude of the change in velocity is given by $|\Delta \vec{v}| = |\vec{v}_B - \vec{v}_A| = 2v \sin(	heta/2)$,where $	heta = 60^{\circ}$.$|\Delta \vec{v}| = 2v \sin(60^{\circ}/2) = 2v \sin(30^{\circ}) = 2v 	imes (1/2) = v$.The magnitude of the velocity is constant $(v)$ throughout the motion. Therefore,the change in the magnitude of the velocity is $v - v = 0$.Thus,the magnitude of the change in velocity is $v$ and the change in the magnitude of velocity is $0$.

Similar Questions

The angular speed of a flywheel making $120 \, \text{revolutions/minute}$ is:

For a particle executing uniform circular motion:

$A$ particle undergoes uniform circular motion. About which point on the plane of the circle will the angular momentum of the particle remain conserved?

Two cars $A$ and $B$ are moving along concentric circular paths of radii $R_A$ and $R_B$. If both cars complete their respective circular paths in the same time,what is the ratio of the angular speed of $A$ to that of $B$?

For a particle moving in a circular path with constant speed,which component of its linear acceleration is constant and which component is not constant?

Vedclass Test Series

Exam Paper Generator

Online Exam Module