A particle moves from position 3hat i + 2hat | vedclass

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(A) The displacement vector $\vec{S}$ is given by the difference between the final position vector $\vec{r_2}$ and the initial position vector $\vec{r

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(A) The displacement vector $\vec{S}$ is given by the difference between the final position vector $\vec{r_2}$ and the initial position vector $\vec{r_1}$.$\vec{S} = \vec{r_2} - \vec{r_1} = (14\hat i + 13\hat j + 9\hat k) - (3\hat i + 2\hat j - 6\hat k) = 11\hat i + 11\hat j + 15\hat k \, m$.Work done $W$ is the dot product of force $\vec{F}$ and displacement $\vec{S}$.$W = \vec{F} \cdot \vec{S} = (4\hat i + \hat j + 3\hat k) \cdot (11\hat i + 11\hat j + 15\hat k)$.$W = (4 	imes 11) + (1 	imes 11) + (3 	imes 15) = 44 + 11 + 45 = 100 \, J$.

$A$ particle moves from position $3\hat i + 2\hat j - 6\hat k$ to $14\hat i + 13\hat j + 9\hat k$ due to a uniform force of $(4\hat i + \hat j + 3\hat k) \, N$. If the displacement is in meters,the work done will be ......... $J$.

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