$A$ particle moves in a circle of radius $5 \; cm$ with constant speed and time period $0.2 \pi \; sec$. The acceleration of the particle is .... $m/sec^2$.

$A$ particle $P$ is moving in a circle of radius $a$ with a uniform speed $v$. $C$ is the centre of the circle and $AB$ is a diameter. When passing through $B$,the angular velocity of $P$ about $A$ and $C$ are in the ratio:

$A$ particle moves so that its position vector is given by $\vec{r} = \cos(\omega t) \hat{i} + \sin(\omega t) \hat{j}$,where $\omega$ is a constant. Which of the following is true?

In Uniform Circular Motion ($U$.$C$.$M$.),when the time interval $\delta t \rightarrow 0$,the angle between the change in velocity $(\delta v)$ and the linear velocity $(v)$ will be (in $^{\circ}$)

Centripetal acceleration of a cyclist completing $7$ rounds in a minute along a circular track of radius $5 \, m$ with a constant speed,is ......... $m/s^2$.

If the linear speed of a particle moving in a circular path is constant,then the angular speed is proportional to (where $r$ is the radius of the circle):