A particle of mass m and charge q moves with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a charged particle enters a perpendicular magnetic field,it follows a circular path of radius $r$ given by the balance between the magnetic f

Vedclass · Accepted Answer

$q(b - a)B/m$

Vedclass · Answer

(B) When a charged particle enters a perpendicular magnetic field,it follows a circular path of radius $r$ given by the balance between the magnetic force and the centripetal force:$qvB = \frac{mv^2}{r}$Rearranging for velocity,we get:$v = \frac{qBr}{m}$For the particle to just enter the region $x > b$,the radius of its circular path must be at least equal to the width of the magnetic field region,which is $(b - a)$.Thus,the minimum radius required is $r_{\min} = b - a$.Substituting this into the velocity equation:$v_{\min} = \frac{qB(b - a)}{m}$Therefore,the correct option is $B$.

Similar Questions

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. The change in collector current is:

During an adiabatic process,the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio $C_P / C_V$ for the gas is

Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A | B)$.

If $R$ is the universal gas constant,the amount of heat needed to raise the temperature of $2 \, mol$ of an ideal monatomic gas from $273 \, K$ to $373 \, K$ when no work is done is: (in $, R$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module