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(B) Given that the particle is at rest,the initial velocity $u = 0$.According to Newton's second law,the acceleration $a$ is given by $a = \frac{P}{m}

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$\frac{P^2 t^2}{2m}$

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(B) Given that the particle is at rest,the initial velocity $u = 0$.According to Newton's second law,the acceleration $a$ is given by $a = \frac{P}{m}$.Using the first equation of motion,$v = u + at$,we get $v = 0 + (\frac{P}{m})t = \frac{Pt}{m}$.The kinetic energy $KE$ is given by the formula $KE = \frac{1}{2}mv^2$.Substituting the value of $v$,we get $KE = \frac{1}{2}m(\frac{Pt}{m})^2$.$KE = \frac{1}{2}m(\frac{P^2 t^2}{m^2}) = \frac{P^2 t^2}{2m}$.

$A$ particle of mass $m$ at rest is acted upon by a force $P$ for a time $t$. Its kinetic energy after an interval $t$ is

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