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(B) The angular momentum $L$ of a particle of mass $m$ moving with velocity $V$ relative to an origin $O$ is given by the formula $L = m 	imes (r 	i

Vedclass · Accepted Answer

$L_A = L_B$

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(B) The angular momentum $L$ of a particle of mass $m$ moving with velocity $V$ relative to an origin $O$ is given by the formula $L = m 	imes (r 	imes V)$,where $r$ is the position vector of the particle.Alternatively,the magnitude of angular momentum is given by $L = m \cdot V \cdot d$,where $d$ is the perpendicular distance from the origin $O$ to the line of motion of the particle.Since the particle is moving along a straight line $AB$,the perpendicular distance $d$ from the origin $O$ to this line remains constant at all points on the line.As $m$,$V$,and $d$ are all constant for the motion of the particle along the line $AB$,the angular momentum $L$ remains constant at all points on the line.Therefore,the angular momentum at point $A$ $(L_A)$ must be equal to the angular momentum at point $B$ $(L_B)$.Thus,$L_A = L_B$.

$A$ particle of mass $m$ moves in the $XY$ plane with a velocity $V$ along the straight line $AB$. If the angular momentum of the particle with respect to origin $O$ is $L_A$ when it is at $A$ and $L_B$ when it is at $B$,then

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