(C) The power delivered to the particle is constant,$P = 0.5 \ W$. Since the initial speed is zero,the initial kinetic energy is $0 \ J$. The work don

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(C) The power delivered to the particle is constant,$P = 0.5 \ W$. Since the initial speed is zero,the initial kinetic energy is $0 \ J$. The work done by the force in time $t = 5 \ s$ is equal to the change in kinetic energy. Work done $W = P \times t = 0.5 \ W \times 5 \ s = 2.5 \ J$. Using the work-energy theorem,$W = \Delta K = \frac{1}{2}mv^2 - 0$. $2.5 \ J = \frac{1}{2} \times 0.2 \ kg \times v^2$. $2.5 = 0.1 \times v^2$. $v^2 = 25$. $v = 5 \ m/s$.

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$A$ particle of mass $0.2 \ kg$ is moving in one dimension under a force that delivers a constant power $0.5 \ W$ to the particle. If the initial speed of the particle is zero,the speed (in $m/s$) after $5 \ s$ is:

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$1$
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$3$
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$5$
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$7$

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$A$ particle of mass $0.2 \ kg$ is moving in one dimension under a force that delivers a constant power $0.5 \ W$ to the particle. If the initial speed of the particle is zero,the speed (in $m/s$) after $5 \ s$ is:

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$A$ man does a given amount of work in $10 \ s$. Another man does the same amount of work in $20 \ s$. The ratio of the output power of the first man to the second man is:

Water falls from a dam at a height of $550 \ m$ onto a turbine at a height of $50 \ m$ at a rate of $2000 \ kg$ per second. If the efficiency of the turbine is $80\%$,the power generated is ............. $MW$.

$A$ body is moving uni-directionally under the influence of a source of constant power. Its displacement in time $t$ is proportional to

$A$ lift raises $50$ passengers, each having an average weight of $600 \,N$, to a height of $100 \,m$ at a constant speed in time $t$. If the average power of $15 \,kW$ is required by the lift, then the value of $t$ in seconds is:

An automobile of mass $m$ accelerates starting from the origin and is initially at rest,while the engine supplies constant power $P$. The position $x$ as a function of time $t$ is given by:

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