A particle starts from origin O from rest and | vedclass

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(D) Given that the particle starts from rest,the initial velocity $u = 0$.Since the particle moves with uniform acceleration,the acceleration $a$ is c

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$a, b, d$

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(D) Given that the particle starts from rest,the initial velocity $u = 0$.Since the particle moves with uniform acceleration,the acceleration $a$ is constant over time.$1$. For acceleration-time graph: Since $a$ is constant,the graph $(a)$ is a horizontal line parallel to the $t$-axis,which is correct.$2$. For velocity-time graph: Using the equation $v = u + at$,we get $v = 0 + at = at$. This represents a straight line passing through the origin,so graph $(b)$ is correct.$3$. For displacement-time graph: Using the equation $x = ut + \frac{1}{2}at^2$,we get $x = 0(t) + \frac{1}{2}at^2 = \frac{1}{2}at^2$. This represents a parabola opening upwards starting from the origin,so graph $(d)$ is correct.Therefore,the figures $(a)$,$(b)$,and $(d)$ correctly represent the motion.

$A$ particle starts from origin $O$ from rest and moves with a uniform acceleration along the positive $x$-axis. Identify all figures that correctly represent the motion qualitatively. ($a =$ acceleration,$v =$ velocity,$x =$ displacement,$t =$ time)

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