A particle with 10^{-11} , C of charge and 10 | vedclass

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(D) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})

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$5 	imes 10^{-4} \, N$ along $-\hat{k}$

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(D) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.Given: $q = 10^{-11} \, C$,$\overrightarrow{v} = 10^8 \hat{j} \, m/s$,and $\overrightarrow{B} = 0.5 \hat{i} \, T$.Substituting these values into the formula:$\overrightarrow{F} = 10^{-11} 	imes (10^8 \hat{j} 	imes 0.5 \hat{i})$$\overrightarrow{F} = 10^{-11} 	imes 10^8 	imes 0.5 	imes (\hat{j} 	imes \hat{i})$Since $\hat{j} 	imes \hat{i} = -\hat{k}$,we get:$\overrightarrow{F} = 0.5 	imes 10^{-3} 	imes (-\hat{k})$$\overrightarrow{F} = 5 	imes 10^{-4} \, N$ along $-\hat{k}$.

$A$ particle with $10^{-11} \, C$ of charge and $10^{-7} \, kg$ mass is moving with a velocity of $10^8 \, m/s$ along the $y$-axis. $A$ uniform static magnetic field $B = 0.5 \, T$ is acting along the $x$-direction. The force on the particle is:

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