(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is

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(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the displacement from the mean position.Given: $|a| = 20 \; m/s^2$ and $y = 5 \; m$.Substituting these values into the formula: $20 = \omega^2 (5)$.$\omega^2 = 4 \Rightarrow \omega = 2 \; rad/s$.The time period $T$ is given by $T = \frac{2\pi}{\omega}$.$T = \frac{2\pi}{2} = \pi \; s$.

Class 11 Physics Oscillations SHM of Simple Pendulum

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

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A
$2\pi \; s$
B
$\pi \; s$
C
$1 \; s$
D
$2 \; s$

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Oscillations

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SHM of Simple Pendulum

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

Similar Questions

$A$ simple pendulum is suspended from the ceiling of a lift. When the lift is at rest,its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T/2$ (in $g$)? ($g$ is acceleration due to gravity).

$A$ simple pendulum has a time period $T$. The bob is given a negative charge and the surface below it is given a positive charge. The new time period will be

$A$ positively charged pendulum is oscillating in a uniform electric field pointing upwards. How does its time period compare to the time period when it oscillates without an electric field?

$A$ simple pendulum with a metallic bob has a time period $T$. The bob is now immersed in a non-viscous liquid and oscillated. If the density of the liquid is $1/4$ that of the metal,the time period of the same pendulum will be ...........

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