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(A) The maximum velocity of the pendulum bob is attained at its lowest position due to the conservation of mechanical energy.Let the length of the str

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$5$

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(A) The maximum velocity of the pendulum bob is attained at its lowest position due to the conservation of mechanical energy.Let the length of the string be $\ell = 250\,cm = 2.5\,m$.The vertical height $h$ through which the bob falls is given by:$h = \ell - \ell \cos 60^{\circ} = \ell(1 - \cos 60^{\circ})$$h = 2.5 	imes (1 - 0.5) = 2.5 	imes 0.5 = 1.25\,m$Using the conservation of energy,the potential energy at the highest point is converted into kinetic energy at the lowest point:$mgh = \frac{1}{2}mv_{\max}^2$$v_{\max} = \sqrt{2gh}$$v_{\max} = \sqrt{2 	imes 10 	imes 1.25} = \sqrt{25} = 5\,m/s$

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