A perfect gas at 27^{circ}C is heated at cons | vedclass

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(C) According to Charles's Law,for a gas at constant pressure,the volume is directly proportional to its absolute temperature: $V \propto T$.Therefore

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$627$

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(C) According to Charles's Law,for a gas at constant pressure,the volume is directly proportional to its absolute temperature: $V \propto T$.Therefore,$\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: Initial temperature $T_1 = 27^{\circ}C = 27 + 273 = 300 \ K$.Initial volume $V_1 = V$.Final volume $V_2 = 3V$.Substituting the values: $\frac{V}{300} = \frac{3V}{T_2}$.$T_2 = 300 	imes 3 = 900 \ K$.To convert the temperature back to Celsius: $t(^{\circ}C) = T(K) - 273$.$t = 900 - 273 = 627^{\circ}C$.

$A$ perfect gas at $27^{\circ}C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be ...... $^{\circ}C$.

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