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(B) Let the speed of the person in still water be $x 	ext{ km/h}$ and the speed of the stream be $y = 2 \frac{1}{4} = 2.25 	ext{ km/h}.$Downstream s

Vedclass · Accepted Answer

$11 \frac{1}{4}$

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(B) Let the speed of the person in still water be $x 	ext{ km/h}$ and the speed of the stream be $y = 2 \frac{1}{4} = 2.25 	ext{ km/h}.$Downstream speed $= (x + y) 	ext{ km/h}.$Upstream speed $= (x - y) 	ext{ km/h}.$Let the distance be $d 	ext{ km}.$According to the problem,$d = (x + y) 	imes 6$ and $d = (x - y) 	imes 9.$Equating the distances: $6(x + y) = 9(x - y).$$6x + 6y = 9x - 9y \implies 3x = 15y \implies x = 5y.$Substituting $y = 2.25 	ext{ km/h}:$$x = 5 	imes 2.25 = 11.25 = 11 \frac{1}{4} 	ext{ km/h}.$

$A$ person can row a certain distance downstream in $6$ $hours$ and return the same distance in $9$ $hours.$ If the stream flows at the rate of $2 \frac{1}{4} \text{ km/h},$ find how far he can row in an hour in still water (in $\text{km/h}$).

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