$A$ person draws a card from a pack of playing cards,replaces it and shuffles the pack. He continues doing this until he draws a spade. The chance that he will fail in the first two attempts is

  • A
    $\frac{9}{64}$
  • B
    $\frac{1}{64}$
  • C
    $\frac{1}{16}$
  • D
    $\frac{9}{16}$

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If the events $A$ and $B$ are mutually exclusive,then $P\left( \frac{A}{B} \right) = $

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