A person in an elevator accelerating upwards | vedclass

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Question

(C) In the frame of the elevator,the coin experiences an effective acceleration due to gravity $(g_{eff})$. Since the elevator is accelerating upwards

Vedclass · Accepted Answer

$\frac{10}{3}\,s$

Vedclass · Answer

(C) In the frame of the elevator,the coin experiences an effective acceleration due to gravity $(g_{eff})$. Since the elevator is accelerating upwards with $a = 2\,ms^{-2}$,the pseudo force acts downwards on the coin.The effective acceleration is $g_{eff} = g + a = 10\,ms^{-2} + 2\,ms^{-2} = 12\,ms^{-2}$.The time taken for the coin to return to the hand is the time of flight in this accelerated frame,given by $t = \frac{2u}{g_{eff}}$,where $u = 20\,ms^{-1}$ is the initial velocity of the coin relative to the elevator.Substituting the values: $t = \frac{2 	imes 20\,ms^{-1}}{12\,ms^{-2}} = \frac{40}{12}\,s = \frac{10}{3}\,s$.

$A$ person in an elevator accelerating upwards with an acceleration of $2\,ms^{-2}$,tosses a coin vertically upwards with a speed of $20\,ms^{-1}$. After how much time will the coin fall back into his hand? (Take $g = 10\,ms^{-2}$)

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