A person needs a lens of power -5.5 , D for c | vedclass

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(B) The power $P$ of a lens is related to its focal length $f$ (in meters) by the formula $P = \frac{1}{f}$.For correcting near vision,the required po

Vedclass · Accepted Answer

$66.7$

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(B) The power $P$ of a lens is related to its focal length $f$ (in meters) by the formula $P = \frac{1}{f}$.For correcting near vision,the required power $P = +1.5 \, D$.Using the formula,$f = \frac{1}{P} = \frac{1}{1.5} \, m$.$f = 0.6666... \, m \approx 0.667 \, m$.To convert the focal length into centimeters $(cm)$,we multiply by $100$:$f = 0.667 	imes 100 \, cm = 66.7 \, cm$.Therefore,the focal length of the lens required for correcting near vision is $66.7 \, cm$.

$A$ person needs a lens of power $-5.5 \, D$ for correcting his distant vision. For correcting his near vision,he needs a lens of power $+1.5 \, D$. What is the focal length (in $cm$) of the lens required for correcting near vision?

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