A person supports a book between his finger a | vedclass

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(B) The weight $W$ of the book acts downwards at its center of mass,which is at a horizontal distance of $\frac{a}{2}$ from the point of grip.The torq

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$W \frac{a}{2}$ anticlockwise

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(B) The weight $W$ of the book acts downwards at its center of mass,which is at a horizontal distance of $\frac{a}{2}$ from the point of grip.The torque $	au$ produced by the weight about the point of grip is given by the product of the force and the perpendicular distance:$	au = 	ext{Force} 	imes 	ext{Perpendicular distance}$$	au = W 	imes \frac{a}{2} = W \frac{a}{2}$Since the weight acts downwards and the pivot point is at the corner,this force creates a rotational tendency in the clockwise direction. To keep the book in equilibrium,the person must apply an equal and opposite torque,which is anticlockwise. Therefore,the person is producing an anticlockwise torque of $W \frac{a}{2}$.

$A$ person supports a book between his finger and thumb as shown (the point of grip is assumed to be at the corner of the book). If the book has a weight of $W$,then the person is producing a torque on the book of

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