A person wears glasses of power -2.5 , D. The | vedclass

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(B) The power of the lens is given as $P = -2.5 \, D$. Since the power is negative,the lens used is a concave lens,which indicates that the person is

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Nearsightedness,$40 \, cm$

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(B) The power of the lens is given as $P = -2.5 \, D$. Since the power is negative,the lens used is a concave lens,which indicates that the person is suffering from myopia or nearsightedness. The focal length $f$ of the lens is given by $f = \frac{1}{P} = \frac{1}{-2.5} \, m = -0.4 \, m = -40 \, cm$. For a person with nearsightedness,the far point is the focal length of the corrective lens used. Therefore,the far point of the person without glasses is $40 \, cm$.

$A$ person wears glasses of power $-2.5 \, D$. The defect of the eye and the far point of the person without the glasses are respectively

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