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(B) According to $Wien's$ displacement law, the product of the wavelength corresponding to maximum intensity $(\lambda_m)$ and the absolute temperatur

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Wien's displacement Law

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(B) According to $Wien's$ displacement law, the product of the wavelength corresponding to maximum intensity $(\lambda_m)$ and the absolute temperature $(T)$ is constant:$\lambda_m T = 	ext{constant}$$\lambda_m = \frac{	ext{constant}}{T}$As the temperature $(T)$ of the iron piece increases, the wavelength $(\lambda_m)$ corresponding to the maximum intensity of emitted radiation decreases. Initially, at lower temperatures, the radiation emitted is in the longer wavelength region (red). As the temperature rises, the peak of the emission spectrum shifts towards shorter wavelengths (reddish-yellow). When the temperature becomes sufficiently high, the object emits radiation across the entire visible spectrum, causing it to appear white-hot.

$A$ piece of iron is heated in a flame. It first becomes dull red, then becomes reddish yellow, and finally turns to white hot. The correct explanation for the above observation is possible by using

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