A pineapple costs Rs. 7 each. A watermelon co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the number of pineapples be $x$ and the number of watermelons be $y$.Given that the cost of one pineapple is $Rs. 7$ and one watermelon is $Rs

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) Let the number of pineapples be $x$ and the number of watermelons be $y$.Given that the cost of one pineapple is $Rs. 7$ and one watermelon is $Rs. 5$.The total expenditure is $Rs. 38$.Therefore,the linear equation is $7x + 5y = 38$,where $x$ and $y$ must be non-negative integers.If $y = 1$,$7x = 38 - 5 = 33$ (not divisible by $7$).If $y = 2$,$7x = 38 - 10 = 28 \Rightarrow x = 4$.If $y = 3$,$7x = 38 - 15 = 23$ (not divisible by $7$).If $y = 4$,$7x = 38 - 20 = 18$ (not divisible by $7$).If $y = 5$,$7x = 38 - 25 = 13$ (not divisible by $7$).If $y = 6$,$7x = 38 - 30 = 8$ (not divisible by $7$).If $y = 7$,$7x = 38 - 35 = 3$ (not divisible by $7$).Thus,the only integer solution is $x = 4$ and $y = 2$.Hence,the number of watermelons purchased is $2$.

$A$ pineapple costs $Rs. 7$ each. $A$ watermelon costs $Rs. 5$ each. $X$ spends $Rs. 38$ on these fruits. The number of watermelons purchased is

Similar Questions

$(0.1 \times 0.01 \times 0.001 \times 10^{7})$ is equal to

$\frac{5}{8}$ of $4011.33 + \frac{7}{10}$ of $3411.22 = ?$

$\frac{0.009}{?} = 0.01$

$\frac{\sqrt{1296}}{?} = \frac{?}{2.25}$

The value of $4-\frac{5}{1+\frac{1}{3+\frac{1}{2+\frac{1}{4}}}}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module