A pipe P can fill a tank in 12 min and anothe | vedclass

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Question

(C) Efficiency of pipe $P = \frac{1}{12}$ tank per minute.Efficiency of pipe $R = \frac{1}{15}$ tank per minute.Efficiency of pipe $M = -\frac{1}{6}$

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) Efficiency of pipe $P = \frac{1}{12}$ tank per minute.Efficiency of pipe $R = \frac{1}{15}$ tank per minute.Efficiency of pipe $M = -\frac{1}{6}$ tank per minute (emptying).Work done by $P$ and $R$ in $5$ minutes $= 5 	imes (\frac{1}{12} + \frac{1}{15}) = 5 	imes (\frac{5+4}{60}) = 5 	imes \frac{9}{60} = \frac{45}{60} = \frac{3}{4}$ of the tank.When all three pipes are open,the net efficiency $= \frac{1}{12} + \frac{1}{15} - \frac{1}{6} = \frac{5+4-10}{60} = -\frac{1}{60}$ tank per minute.The negative sign indicates that the tank is being emptied at a rate of $\frac{1}{60}$ tank per minute.Time taken to empty $\frac{3}{4}$ of the tank $= \frac{3/4}{1/60} = \frac{3}{4} 	imes 60 = 45$ minutes.

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