A planet is observed by an astronomical refra | vedclass

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(D) For an astronomical telescope in normal adjustment,the distance between the objective and the eye-piece is $L = f_o + f_e$. Given $f_o = 16 \, m$

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All of the above.

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(D) For an astronomical telescope in normal adjustment,the distance between the objective and the eye-piece is $L = f_o + f_e$. Given $f_o = 16 \, m$ and $f_e = 2 \, cm = 0.02 \, m$,so $L = 16 + 0.02 = 16.02 \, m$. Statement $A$ is correct.The angular magnification $m$ is given by $m = -f_o / f_e = -16 / 0.02 = -800$. The magnitude of magnification is $800$. Statement $B$ is correct.The negative sign in the magnification indicates that the final image formed by an astronomical telescope is inverted with respect to the object. Statement $C$ is correct.Since all statements $A, B,$ and $C$ are correct,the correct option is $D$.

$A$ planet is observed by an astronomical refracting telescope having an objective of focal length $16 \, m$ and an eye-piece of focal length $2 \, cm$. Which of the following statements is correct?

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