$A$ plot of $\log (x/m)$ versus $\log p$ for the adsorption of a gas on a solid gives a straight line with slope equal to
- A$\log K$
- B$-\log K$
- C$n$
- D$1/n$
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Similar Questions
Noble gases are adsorbed by
Medium
View SolutionThe correct option$(s)$ related to adsorption processes is(are):
$A$. Chemisorption results in a unimolecular layer.
$B$. The enthalpy change during physisorption is in the range of $100$ to $140 \ kJ \ mol^{-1}$.
$C$. Chemisorption is an endothermic process.
$D$. Lowering the temperature favors physisorption processes.
$A$. Chemisorption results in a unimolecular layer.
$B$. The enthalpy change during physisorption is in the range of $100$ to $140 \ kJ \ mol^{-1}$.
$C$. Chemisorption is an endothermic process.
$D$. Lowering the temperature favors physisorption processes.
DifficultIIT 2022
View SolutionAssertion : Physical adsorption of molecules takes place on the surface only.
Reason : In this process,the bonds of the adsorbed molecules are broken.
Reason : In this process,the bonds of the adsorbed molecules are broken.
MediumAIIMS 2002
View SolutionWhat should be taken on the $Y$-axis in the Freundlich adsorption isotherm plot to obtain a straight line?
Easy
View SolutionWhy is $Fe(OH)_3$ colloid positively charged when prepared by adding $FeCl_3$ to hot water?
Medium
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