A point object on the principal axis at a dis | vedclass

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(B) Given: Object distance $u = -15\, cm$,Radius of curvature $R = -20\, cm$.Focal length $f = R/2 = -10\, cm$.Using the mirror formula: $1/v + 1/u =

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$4$

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(B) Given: Object distance $u = -15\, cm$,Radius of curvature $R = -20\, cm$.Focal length $f = R/2 = -10\, cm$.Using the mirror formula: $1/v + 1/u = 1/f$.$1/v = 1/f - 1/u = 1/(-10) - 1/(-15) = -1/10 + 1/15 = (-3 + 2)/30 = -1/30$.So,$v = -30\, cm$.Magnification $m = -v/u = -(-30)/(-15) = -2$.The velocity of the image perpendicular to the principal axis is given by $v_i = m 	imes v_o$.$v_i = -2 	imes 2\, mm/s = -4\, mm/s$.The magnitude of the velocity is $|v_i| = 4\, mm/s$.

$A$ point object on the principal axis at a distance $15\, cm$ in front of a concave mirror of radius of curvature $20\, cm$ has a velocity of $2\, mm/s$ perpendicular to the principal axis. The velocity of the image at that instant will be.......$mm/s$.

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