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(D) Let the mirror be $AB$ with length $d$. The light source $S$ is at a distance $L$ from the mirror. The man walks at a distance $2L$ from the mirro

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$3d$

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(D) Let the mirror be $AB$ with length $d$. The light source $S$ is at a distance $L$ from the mirror. The man walks at a distance $2L$ from the mirror.$1$. The image of the source $S$ is formed behind the mirror at a distance $L$. Let this image be $S'$.$2$. The rays from the source $S$ reflect off the edges of the mirror $A$ and $B$. These reflected rays appear to come from $S'$.$3$. The field of view is determined by the rays passing through the edges $A$ and $B$ of the mirror. $4$. By similar triangles,the width of the field of view at a distance $2L$ from the mirror is $3d$. $5$. Specifically,the distance between the extreme rays at the man's path is $GJ = GH + HI + IJ$. Since $HI = d$ and $GH = IJ = d$,the total distance is $3d$.

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