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(C) Let the distance covered in one step of the policeman be $P$ and that of the thief be $T$.Given that $5P = 7T$, therefore $P/T = 7/5$.In the same

Vedclass · Accepted Answer

$28:25$

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(C) Let the distance covered in one step of the policeman be $P$ and that of the thief be $T$.Given that $5P = 7T$, therefore $P/T = 7/5$.In the same time interval, the policeman takes $8$ steps and the thief takes $10$ steps.Distance covered by the policeman in $8$ steps $= 8P$.Distance covered by the thief in $10$ steps $= 10T$.The ratio of their speeds is the ratio of the distances covered in the same time:$	ext{Ratio} = (8P) / (10T) = (8/10) 	imes (P/T)$.Substituting $P/T = 7/5$:$	ext{Ratio} = (8/10) 	imes (7/5) = 56 / 50 = 28 / 25$.Thus, the ratio of the speeds of the policeman and the thief is $28:25$.

$A$ policeman starts to chase a thief. When the thief goes $10 \, \text{steps}$, the policeman moves $8 \, \text{steps}$. $5 \, \text{steps}$ of the policeman are equal to $7 \, \text{steps}$ of the thief. The ratio of the speeds of the policeman and the thief is

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