$A$ precipitate of which of the following is obtained when $HCl$ is added to a solution of stannous sulphide $(SnS)$ in yellow ammonium sulphide?

Upon treatment with ammoniacal $H_2S$,the metal ion that precipitates as a sulfide is

Match List-$I$ with List-$II$.

$LIST$-$I$ (Precipitating reagent and conditions)	$LIST$-$II$ (Cation)
$A$. $NH_4Cl + NH_4OH$	$I$. $Mn^{2+}$
$B$. $NH_4OH + (NH_4)_2CO_3$	$II$. $Pb^{2+}$
$C$. $NH_4OH + NH_4Cl + H_2S$ gas	$III$. $Al^{3+}$
$D$. Dilute $HCl$	$IV$. $Sr^{2+}$

Choose the correct answer from the options given below:

On treating a solid salt $A$ with dil. $H_2SO_4$ and warming,reddish-brown fumes of gas $B$ are evolved. Addition of $C$ to the salt solution of $A$ followed by freshly prepared starch solution and acidification with acetic acid produces a blue colour. $C$ may contain:

The reagent that can distinguish between silver and lead salt is

An aqueous solution of an inorganic salt on treatment with $HCl$ gives a white precipitate. This solution contains