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(B) For a direct vision spectroscope,the net deviation produced by the combination of two prisms must be zero.Let $A_1$ and $A_2$ be the angles of the

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(B) For a direct vision spectroscope,the net deviation produced by the combination of two prisms must be zero.Let $A_1$ and $A_2$ be the angles of the crown and flint glass prisms,and $\mu_1$ and $\mu_2$ be their respective refractive indices.The condition for zero net deviation is given by: $(\mu_1 - 1)A_1 + (\mu_2 - 1)A_2 = 0$.Since the prisms are arranged to produce opposite deviations,we have: $(\mu_1 - 1)A_1 = (\mu_2 - 1)A_2$.Given: $A_1 = 9^{\circ}$,$\mu_1 = 1.40$,and $\mu_2 = 1.60$.Substituting the values: $(1.40 - 1) 	imes 9^{\circ} = (1.60 - 1) 	imes A_2$.$0.40 	imes 9^{\circ} = 0.60 	imes A_2$.$3.6^{\circ} = 0.60 	imes A_2$.$A_2 = \frac{3.6}{0.6} = 6^{\circ}$.

$A$ prism of crown glass with a prism angle of $9^{\circ}$ and a prism of flint glass are used to make a direct vision spectroscope. If the refractive indices of crown and flint glass are $1.40$ and $1.60$ respectively,then the refracting angle of the flint glass prism will be.....$^{\circ}$

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