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(D) Let $A, B,$ and $C$ be the events that the three students solve the problem respectively.Given probabilities are $P(A) = \frac{1}{3}$,$P(B) = \fra

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$\frac{3}{5}$

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(D) Let $A, B,$ and $C$ be the events that the three students solve the problem respectively.Given probabilities are $P(A) = \frac{1}{3}$,$P(B) = \frac{1}{4}$,and $P(C) = \frac{1}{5}$.The probability that they do not solve the problem are $P(A') = 1 - \frac{1}{3} = \frac{2}{3}$,$P(B') = 1 - \frac{1}{4} = \frac{3}{4}$,and $P(C') = 1 - \frac{1}{5} = \frac{4}{5}$.The probability that the problem is not solved by any of them is $P(A' \cap B' \cap C') = P(A') 	imes P(B') 	imes P(C') = \frac{2}{3} 	imes \frac{3}{4} 	imes \frac{4}{5} = \frac{2}{5}$.Therefore,the probability that the problem is solved is $1 - P(A' \cap B' \cap C') = 1 - \frac{2}{5} = \frac{3}{5}$.

$A$ problem of mathematics is given to three students whose chances of solving the problem are $\frac{1}{3}$,$\frac{1}{4}$,and $\frac{1}{5}$ respectively. The probability that the question will be solved is

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