(B) The energy of the light pulse is given by $E = P \times t$,where $P$ is the power and $t$ is the duration.Given $P = 30 \ mW = 30 \times 10^{-3} \

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$1.0 \times 10^{-17} \ kg \cdot m/s$

(B) The energy of the light pulse is given by $E = P \times t$,where $P$ is the power and $t$ is the duration.Given $P = 30 \ mW = 30 \times 10^{-3} \ W$ and $t = 100 \ ns = 100 \times 10^{-9} \ s$.$E = (30 \times 10^{-3}) \times (100 \times 10^{-9}) = 3000 \times 10^{-12} = 3 \times 10^{-9} \ J$.When light is completely absorbed,the momentum $p$ transferred to the object is given by $p = E/c$,where $c$ is the speed of light.$p = \frac{3 \times 10^{-9} \ J}{3 \times 10^8 \ m/s} = 1 \times 10^{-17} \ kg \cdot m/s$.

Class 12 Physics Dual Nature of Radiation and Matter Radiation Force and Pressure

Difficult

$A$ pulse of light of duration $100 \ ns$ is absorbed completely by a small object initially at rest. The power of the pulse is $30 \ mW$ and the speed of light is $3 \times 10^8 \ m/s$. The final momentum of the object is:

IIT 2013 All IIT

A
$0.3 \times 10^{-17} \ kg \cdot m/s$
B
$1.0 \times 10^{-17} \ kg \cdot m/s$
C
$3.0 \times 10^{-17} \ kg \cdot m/s$
D
$9.0 \times 10^{-17} \ kg \cdot m/s$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Dual Nature of Radiation and Matter

Subtopic

Radiation Force and Pressure

Previous Year

IIT 2013 Paper All IIT years →

$A$ photon of wavelength $6630 \ \mathring{A}$ is incident on a totally reflecting surface. The momentum delivered by the photon is equal to

Medium

View Solution

If electromagnetic waves of power $600 \ W$ are incident on a non-reflecting surface,then the total force acting on the surface is

MediumTS EAMCET 2025

View Solution

Light with an energy flux of $25 \times 10^4 \, W/m^2$ falls on a perfectly reflecting surface at normal incidence. If the surface area is $15 \, cm^2$,the average force exerted on the surface is:

MediumAIPMT 2014

View Solution

$A$ parallel beam of monochromatic light of frequency $\nu$ is incident on a surface. The intensity of the beam is $I$ and the area of the surface is $A$. Find the force exerted by the light beam on the surface if it is perfectly reflecting and the light beam is incident at an angle of incidence $\theta$. (The speed of light is denoted as $c$.)

EasyTS EAMCET 2019

View Solution

$50\, W/m^2$ energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy $(25\%)$ is reflected from the surface and the rest is absorbed. The force exerted on $1\, m^2$ surface area will be close to $(c = 3 \times 10^8\, m/s)$.

DifficultJEE MAIN 2019

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ pulse of light of duration $100 \ ns$ is absorbed completely by a small object initially at rest. The power of the pulse is $30 \ mW$ and the speed of light is $3 \times 10^8 \ m/s$. The final momentum of the object is:

Similar Questions

$A$ photon of wavelength $6630 \ \mathring{A}$ is incident on a totally reflecting surface. The momentum delivered by the photon is equal to

If electromagnetic waves of power $600 \ W$ are incident on a non-reflecting surface,then the total force acting on the surface is

Light with an energy flux of $25 \times 10^4 \, W/m^2$ falls on a perfectly reflecting surface at normal incidence. If the surface area is $15 \, cm^2$,the average force exerted on the surface is:

$50\, W/m^2$ energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy $(25\%)$ is reflected from the surface and the rest is absorbed. The force exerted on $1\, m^2$ surface area will be close to $(c = 3 \times 10^8\, m/s)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module