A radioactive nucleus decays as follows:X xri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In $\alpha$ decay,the mass number decreases by $4$ and the atomic number decreases by $2$.In $\beta$ decay,the mass number remains constant,but th

Vedclass · Accepted Answer

$172, 69$

Vedclass · Answer

(C) In $\alpha$ decay,the mass number decreases by $4$ and the atomic number decreases by $2$.In $\beta$ decay,the mass number remains constant,but the atomic number increases by $1$.In $\gamma$ decay,both the mass number and the atomic number remain constant.Given initial nucleus $X$ has mass number $A = 180$ and atomic number $Z = 72$.Step $1$: $X \xrightarrow{\alpha} X_1$$A_1 = 180 - 4 = 176$,$Z_1 = 72 - 2 = 70$.Step $2$: $X_1 \xrightarrow{\beta} X_2$$A_2 = 176$,$Z_2 = 70 + 1 = 71$.Step $3$: $X_2 \xrightarrow{\alpha} X_3$$A_3 = 176 - 4 = 172$,$Z_3 = 71 - 2 = 69$.Step $4$: $X_3 \xrightarrow{\gamma} X_4$$A_4 = 172$,$Z_4 = 69$.Thus,the mass number of $X_4$ is $172$ and the atomic number is $69$.

$A$ radioactive nucleus decays as follows:
$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$
If the atomic number and the mass number of $X$ are $72$ and $180$ respectively,then the mass number and atomic number of $X_4$ are:

Similar Questions

$A$ radioactive element $_{90}X^{238}$ decays into $_{83}Y^{222}$. The number of $\beta$-particles emitted is:

In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted will be

When ${}_{92}U^{238}$ changes into ${}_{82}Pb^{206}$,the number of $\alpha$ and $\beta^-$ particles emitted are:

In the nuclear decay sequence given below:
$_Z{X^A} \to {}_{Z + 1}{Y^A} \to {}_{Z - 1}{K^{A - 4}} \to {}_{Z - 1}{K^{A - 4}}$
the particles emitted in the sequence are:

In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted is $x$ and the number of $\beta$-particles emitted is $y$. Find $x$ and $y$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ radioactive nucleus decays as follows:$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$If the atomic number and the mass number of $X$ are $72$ and $180$ respectively,then the mass number and atomic number of $X_4$ are: