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(C) For a radioactive sample undergoing two independent decay processes with decay constants $\lambda_1$ and $\lambda_2$,the total decay constant is $

Vedclass · Accepted Answer

$T_{1/2} = \frac{T_{1/2}^{(1)} T_{1/2}^{(2)}}{T_{1/2}^{(1)} + T_{1/2}^{(2)}}$

Vedclass · Answer

(C) For a radioactive sample undergoing two independent decay processes with decay constants $\lambda_1$ and $\lambda_2$,the total decay constant is $\lambda_{eq} = \lambda_1 + \lambda_2$.Since the decay constant $\lambda$ is related to the half-life $T_{1/2}$ by the formula $\lambda = \frac{\ln 2}{T_{1/2}}$,we can write:$\frac{\ln 2}{T_{1/2}} = \frac{\ln 2}{T_{1/2}^{(1)}} + \frac{\ln 2}{T_{1/2}^{(2)}}$.Dividing both sides by $\ln 2$,we get:$\frac{1}{T_{1/2}} = \frac{1}{T_{1/2}^{(1)}} + \frac{1}{T_{1/2}^{(2)}}$.Solving for $T_{1/2}$,we find:$T_{1/2} = \frac{T_{1/2}^{(1)} T_{1/2}^{(2)}}{T_{1/2}^{(1)} + T_{1/2}^{(2)}}$.

$A$ radioactive sample disintegrates via two independent decay processes having half-lives $T_{1/2}^{(1)}$ and $T_{1/2}^{(2)}$ respectively. The effective half-life $T_{1/2}$ of the nuclei is

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