A ray of light strikes a plane mirror M at an | vedclass

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(C) The total deviation $\delta_{	ext{net}}$ is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviatio

Vedclass · Accepted Answer

$92$

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(C) The total deviation $\delta_{	ext{net}}$ is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviation by the plane mirror: $\delta_{	ext{mirror}} = 180^o - 2i$,where $i$ is the angle of incidence. Given $i = 45^o$,$\delta_{	ext{mirror}} = 180^o - 2(45^o) = 90^o$.$2$. Deviation by the thin prism: $\delta_{	ext{prism}} = (\mu - 1)A$,where $\mu = 1.5$ is the refractive index and $A = 4^o$ is the apex angle. $\delta_{	ext{prism}} = (1.5 - 1) 	imes 4^o = 0.5 	imes 4^o = 2^o$.$3$. Total deviation: $\delta_{	ext{net}} = \delta_{	ext{mirror}} + \delta_{	ext{prism}} = 90^o + 2^o = 92^o$.

$A$ ray of light strikes a plane mirror $M$ at an angle of $45^o$ as shown in the figure. After reflection,the ray passes through a prism of refractive index $1.5$ whose apex angle is $4^o$. The total angle through which the ray is deviated is......$^o$

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