A reaction between CH_3MgBr (methyl magnesium | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Grignard reagents $(RMgX)$ are strong bases and react with compounds containing active hydrogen atoms (like alcohols,water,or amines) to form alka

Vedclass · Accepted Answer

Methane

Vedclass · Answer

(A) Grignard reagents $(RMgX)$ are strong bases and react with compounds containing active hydrogen atoms (like alcohols,water,or amines) to form alkanes.The reaction is as follows:$C_2H_5OH + CH_3MgBr \rightarrow CH_4 + Mg(OC_2H_5)Br$Here,the $CH_3^-$ group from the Grignard reagent abstracts the acidic proton $(H^+)$ from the ethyl alcohol $(C_2H_5OH)$ to form methane $(CH_4)$.

$A$ reaction between $CH_3MgBr$ (methyl magnesium bromide) and $C_2H_5OH$ (ethyl alcohol) gives:

Similar Questions

Out of $2$-chloroethanol and ethanol,which is more acidic and why?

$A$ compound $A$ on oxidation gives acetaldehyde,and further oxidation gives an acid. After the first oxidation,the product reacts with ammoniacal $AgNO_3$ to produce a silver mirror. Compound $A$ is likely to be:

Methyl alcohol can be distinguished from ethyl alcohol using

Find the missing reagents $(x)$ and $(y)$ for the following reaction sequence:

Which of the following responds to a positive $(+ve)$ iodoform test?

Vedclass Test Series

Exam Paper Generator

Online Exam Module