A reduction of 10 % in the price of tea enabl | vedclass

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(C) Let the original price of tea be $x$ per $kg$.Total amount available $= Rs \ 22500$.Original quantity of tea purchased $= \frac{22500}{x} \ kg$.Re

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(C) Let the original price of tea be $x$ per $kg$.Total amount available $= Rs \ 22500$.Original quantity of tea purchased $= \frac{22500}{x} \ kg$.Reduced price of tea $= 0.9x$ per $kg$.New quantity of tea purchased $= \frac{22500}{0.9x} \ kg$.According to the problem,the difference in quantity is $25 \ kg$:$\frac{22500}{0.9x} - \frac{22500}{x} = 25$$\frac{25000}{x} - \frac{22500}{x} = 25$$\frac{2500}{x} = 25$$x = 100$.The original price is $Rs \ 100$ per $kg$.The reduced price $= 0.9 	imes 100 = Rs \ 90$ per $kg$.

$A$ reduction of $10 \%$ in the price of tea enables a dealer to purchase $25 \ kg$ more tea for $Rs \ 22500$. What is the reduced price per $kg$ of tea?

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