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(B) Temperature inside the refrigerator,$T_{1} = 9^{\circ} C = 282 \ K$.Room temperature,$T_{2} = 36^{\circ} C = 309 \ K$.The coefficient of performan

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$10.44$

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(B) Temperature inside the refrigerator,$T_{1} = 9^{\circ} C = 282 \ K$.Room temperature,$T_{2} = 36^{\circ} C = 309 \ K$.The coefficient of performance $(COP)$ for a Carnot refrigerator is given by the formula:$COP = \frac{T_{1}}{T_{2} - T_{1}}$Substituting the values:$COP = \frac{282}{309 - 282}$$COP = \frac{282}{27}$$COP = 10.44$Therefore,the coefficient of performance of the given refrigerator is $10.44$.

$A$ refrigerator is to maintain eatables kept inside at $9^{\circ} C$. If room temperature is $36^{\circ} C$,calculate the coefficient of performance.

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