A resistor dissipates 192 , J of energy in 1 | vedclass

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(D) The energy dissipated by a resistor is given by the formula $E = i^2 Rt$,where $i$ is the current,$R$ is the resistance,and $t$ is the time.Given:

Vedclass · Accepted Answer

$3840$

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(D) The energy dissipated by a resistor is given by the formula $E = i^2 Rt$,where $i$ is the current,$R$ is the resistance,and $t$ is the time.Given: $E_1 = 192 \, J$,$i_1 = 4 \, A$,$t_1 = 1 \, s$.Substituting these values: $192 = (4)^2 	imes R 	imes 1$.$192 = 16 	imes R \implies R = \frac{192}{16} = 12 \, \Omega$.Now,the current is doubled,so $i_2 = 2 	imes 4 = 8 \, A$.The time is $t_2 = 5 \, s$.The new energy dissipated is $E_2 = i_2^2 	imes R 	imes t_2$.$E_2 = (8)^2 	imes 12 	imes 5$.$E_2 = 64 	imes 12 	imes 5 = 64 	imes 60 = 3840 \, J$.

$A$ resistor dissipates $192 \, J$ of energy in $1 \, s$ when a current of $4 \, A$ is passed through it. Now,when the current is doubled,the amount of thermal energy dissipated in $5 \, s$ is $..... \, J$.

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