A rhombus shaped field has green grass for 18 | vedclass

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(D) Here,each side of the rhombus $= 30\, m$.One of the diagonals $= 48\, m$.Since a diagonal divides the rhombus into two congruent triangles,the sid

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$48$

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(D) Here,each side of the rhombus $= 30\, m$.One of the diagonals $= 48\, m$.Since a diagonal divides the rhombus into two congruent triangles,the sides of the first triangle are $a = 30\, m, b = 30\, m, c = 48\, m$.The semi-perimeter $s = \frac{a + b + c}{2} = \frac{30 + 30 + 48}{2}\, m = \frac{108}{2} = 54\, m$.Area of triangle $I = \sqrt{s(s - a)(s - b)(s - c)} = \sqrt{54(54 - 30)(54 - 30)(54 - 48)}\, m^{2}$.$= \sqrt{54 	imes 24 	imes 24 	imes 6}\, m^{2} = \sqrt{(9 	imes 6) 	imes 24 	imes 24 	imes 6}\, m^{2} = \sqrt{9 	imes 36 	imes 24^{2}}\, m^{2} = 3 	imes 6 	imes 24\, m^{2} = 432\, m^{2}$.Area of the second triangle is also $432\, m^{2}$.Total area of the rhombus $= 432\, m^{2} + 432\, m^{2} = 864\, m^{2}$.Thus,the area of grass for $18$ cows $= 864\, m^{2}$.Area of grass for $1$ cow $= \frac{864}{18}\, m^{2} = 48\, m^{2}$.

$A$ rhombus shaped field has green grass for $18$ cows to graze. If each side of the rhombus is $30\, m$ and its longer diagonal is $48\, m$,how much area of grass field will each cow be getting (in $, m^{2}$)?

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