A right circular cylinder has a mass m,radius | vedclass

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Question

(D) The net force on the cylinder is the difference between the buoyant force $(F_b)$ acting upwards and the gravitational force $(mg)$ acting downwar

Vedclass · Accepted Answer

$\pi r^2\rho gh - mg$

Vedclass · Answer

(D) The net force on the cylinder is the difference between the buoyant force $(F_b)$ acting upwards and the gravitational force $(mg)$ acting downwards.The volume of the cylinder is $V = \pi r^2 h$.The buoyant force is given by Archimedes' principle: $F_b = \rho V g = \rho (\pi r^2 h) g = \pi r^2 \rho g h$.The gravitational force acting on the cylinder is $F_g = mg$.Therefore,the net force $F_{net}$ is:$F_{net} = F_b - F_g = \pi r^2 \rho g h - mg$.

$A$ right circular cylinder has a mass $m$,radius $r$,and a height $h$. The cylinder is completely submerged in a fluid of density $\rho$,as shown in the diagram. What is the magnitude of the net force on the cylinder?

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